Get The Sum Of All Specified Elements In An Array Of Objects

I have an array of objects as folllows [ {'width':128.90663423245883,'height':160,'X':0,'Y':140}, {'width':277.0938568683375,'height':263,'X':128.90663423245883,'Y':37},

Solution 1:

For an easier and more reusable code pass to the method the object and the index, as follows:

function getAllBefore(obj, index){
  var sum=0;
  for(var i=0; i<index; i++){
    sum+=obj[i].width;
  }

  returnsum;
}

And call it like this:

getAllBefore(obj, 5);

Solution 2:

Here is an example using a slice to first return the array with the correct length and the a reduce to return the sum

constgetSum = (objNum, arr) => {
  const newArr =  arr.slice(0, objNum - 1)
  return newArr.reduce((current, next) => {
    return current + next.width;
  }, 0)
}

and in ES5

vargetSum = (objNum, arr) => {
  vat newArr =  arr.slice(0, objNum - 1)
  return newArr.reduce(function(current, next) {
    return current + next.width;
  }, 0)
}

and in 1 line

constgetSum = (objNum, arr) => arr.slice(0, objNum - 1).reduce((current, next) =>  current + next.width, 0)

Solution 3:

Let's use reduce in JavaScript

var arr = [
    {"width":128.90663423245883,"height":160,"X":0,"Y":140},
    {"width":277.0938568683375,"height":263,"X":128.90663423245883,"Y":37},
    {"width":264.8267031014369,"height":261,"X":277.0938568683375,"Y":39},
    {"width":229.14003389179788,"height":60,"X":264.8267031014369,"Y":240},
    {"width":10.032771905968888,"height":177,"X":229.14003389179788,"Y":123}
];

console.log(arr.reduce((acc, b) => acc + b.width, 0.0));

Solution 4:

If you are looking for solution without knowing index of element but you want only to send object, then you will need to check all properties of current item with available items and you can do it like this:

var items = [
{"width":128.90663423245883,"height":160,"X":0,"Y":140},
{"width":277.0938568683375,"height":263,"X":128.90663423245883,"Y":37},
{"width":264.8267031014369,"height":261,"X":277.0938568683375,"Y":39},
{"width":229.14003389179788,"height":60,"X":264.8267031014369,"Y":240},
{"width":10.032771905968888,"height":177,"X":229.14003389179788,"Y":123}
];

functiongetAllBefore(current) {
    var sum = 0;

    for (var i = 0; i < items.length; i++) {
        var item = items[i];
        if (current.width == item.width && current.height == item.height && current.X == item.X && current.Y == item.Y)
        {
             return sum;
        }

        sum += item.width;
    }
}

getAllBefore(items[2]);

Solution 5:

functioncount(stack) {
    var totWidth = 0;
    stack.forEach(function(element) {
      totWidth = totWidth+element.width;
    });
  return totWidth;
}

working example