Regular Expression For Password With Few Rules

I want a function checkPassword function, which should check if the password parameter adheres to the following rules: Must be longer than 6 characters Allowed characters are lowe

Solution 1:

You can use the following regex and get the content of the capturing group to check if your string is valid:

.*\d{3}.*|^([\w\+$#/\\]{6,})$

Working demo

Using \w allows A-Za-z0-9_ if you don't want underscore on your regex you have to replace \w by A-Za-z0-9

For the following examples:

pass12p            --> Pass
pass125p           --> Won't pass
asdfasf12asdf34    --> Pass
asdfasf12345asdf34 --> Won't pass

Match information is:

MATCH 1
1.`pass12p`
MATCH 2
1.`asdfasf12asdf34`

Solution 2:

The best way would be to use two separate regular expressions. First, make sure the password matches this first one, which checks for adherence to rules #1 and #2:

[A-Za-z0-9#$\/\\\+]{6,}

Then, make sure the password does not match this second regular expression, which checks for the presence of a sequence of 3 consecutive numbers anywhere in the password:

\d{3}

Solution 3:

functioncheckPassword(str) {
  console.log( /^(?!.*\d{3})[+a-z\d$#\\/]{6,}$/i.test(str) );
}